16q^2-23q+7=

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Solution for 16q^2-23q+7= equation:


Simplifying
16q2 + -23q + 7 = 0

Reorder the terms:
7 + -23q + 16q2 = 0

Solving
7 + -23q + 16q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(7 + -16q)(1 + -1q) = 0

Subproblem 1

Set the factor '(7 + -16q)' equal to zero and attempt to solve: Simplifying 7 + -16q = 0 Solving 7 + -16q = 0 Move all terms containing q to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -16q = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -16q = 0 + -7 -16q = 0 + -7 Combine like terms: 0 + -7 = -7 -16q = -7 Divide each side by '-16'. q = 0.4375 Simplifying q = 0.4375

Subproblem 2

Set the factor '(1 + -1q)' equal to zero and attempt to solve: Simplifying 1 + -1q = 0 Solving 1 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1q = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1q = 0 + -1 -1q = 0 + -1 Combine like terms: 0 + -1 = -1 -1q = -1 Divide each side by '-1'. q = 1 Simplifying q = 1

Solution

q = {0.4375, 1}

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